3^2x+1=7^x+1

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Solution for 3^2x+1=7^x+1 equation: 



3^2x+1=7^x+1

We move all terms to the left:

3^2x+1-(7^x+1)=0

We get rid of parentheses

3^2x-7^x-1+1=0

We add all the numbers together, and all the variables

3^2x-7^x=0

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